Fluorine reacts with dilute NaOH to form a ga | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of fluorine with dilute $NaOH$ is given by: $2F_2 + 2NaOH \rightarrow 2NaF + OF_2 + H_2O$ Thus, the gaseous product $A$ is oxygen dif

Vedclass · Accepted Answer

$103^{\circ}$

Vedclass · Answer

(B) The reaction of fluorine with dilute $NaOH$ is given by: $2F_2 + 2NaOH \rightarrow 2NaF + OF_2 + H_2O$ Thus, the gaseous product $A$ is oxygen difluoride $(OF_2)$. In $OF_2$, the central oxygen atom is $sp^3$ hybridized. It has two bond pairs and two lone pairs of electrons. Due to the strong repulsion between the two lone pairs of electrons on the oxygen atom, the bond angle is compressed from the ideal tetrahedral angle of $109^{\circ} 28^{\prime}$ to $103^{\circ}$.

Fluorine reacts with dilute $NaOH$ to form a gaseous product $A$. The bond angle in the molecule of $A$ is

Similar Questions

Bromine is commercially prepared from sea water by displacement reaction:
$Cl_2 + 2Br^{-} (aq.) \to 2Cl^{-}(aq.) + Br_2$
$Br_2$ gas thus formed is dissolved into a solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with:

Fluorine reacts with water to give

The reaction of concentrated $H_2SO_4$ with $KI$ does not produce $HI$ because........

When $KBr$ is treated with concentrated $H_2SO_4$,a reddish-brown gas is evolved. The gas is:

In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
$\underline{I}OF_5 + 2H_2O \longrightarrow HIO_4 + 5HF$

Vedclass Test Series

Exam Paper Generator

Online Exam Module