Following four solutions are prepared by mixi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For $pH = 1$,the concentration of $[H^{+}]$ must be $10^{-1} \ M$ or $0.1 \ M$ $(M/10)$.For option $B$: $75 \ mL \ \frac{M}{5} \ HCl + 25 \ mL \ \

Vedclass · Accepted Answer

$75 \ mL \ \frac{M}{5} \ HCl + 25 \ mL \ \frac{M}{5} \ NaOH$

Vedclass · Answer

(B) For $pH = 1$,the concentration of $[H^{+}]$ must be $10^{-1} \ M$ or $0.1 \ M$ $(M/10)$.For option $B$: $75 \ mL \ \frac{M}{5} \ HCl + 25 \ mL \ \frac{M}{5} \ NaOH$.$25 \ mL \ \frac{M}{5} \ NaOH$ will neutralize $25 \ mL \ \frac{M}{5} \ HCl$.Remaining $HCl$ volume = $75 \ mL - 25 \ mL = 50 \ mL$ of $\frac{M}{5} \ HCl$.Total volume of the solution = $75 \ mL + 25 \ mL = 100 \ mL$.New concentration of $HCl = \frac{M}{5} 	imes \frac{50 \ mL}{100 \ mL} = \frac{M}{10} = 0.1 \ M$.Since $HCl$ is a strong acid,$[H^{+}] = 0.1 \ M$.$pH = -\log_{10}[H^{+}] = -\log_{10}(10^{-1}) = 1$.

Following four solutions are prepared by mixing different volumes of $NaOH$ and $HCl$ of different concentrations. The $pH$ of which one of them will be equal to $1$?

Similar Questions

Calculate the $pOH$ of $0.10 \ M \ HCl$ solution.

What is the $pH$ of $1 \text{ M } HCl$ solution? (Assume complete dissociation)

If the $pH$ of a solution of an alkali metal hydroxide is $13.6$,the concentration of hydroxide is

What is the $pH$ of $1 \times 10^{-4} \ M \ H_2SO_4$ solution?

Which of the following solutions will have $pH$ close to $1.0$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module