Following is the frequency distribution of total marks obtained by the students of different sections of Class $VIII.$

Marks	$100-150$	$150-200$	$200-300$	$300-500$	$500-800$
Number of students	$60$	$100$	$100$	$80$	$180$

Draw a histogram for the distribution above.

(N/A) In the given frequency distribution,the class intervals are not of equal width. Therefore,we must modify the lengths of the rectangles in the histogram so that the areas of the rectangles are proportional to the frequencies. The minimum class width is $50$. We calculate the adjusted length (frequency density) as: $\text{Length of rectangle} = \frac{\text{Minimum class width}}{\text{Class width}} \times \text{Frequency}$.

Marks	Frequency	Width of the class	Length of the rectangle
$100-150$	$60$	$50$	$\frac{50}{50} \times 60 = 60$
$150-200$	$100$	$50$	$\frac{50}{50} \times 100 = 100$
$200-300$	$100$	$100$	$\frac{50}{100} \times 100 = 50$
$300-500$	$80$	$200$	$\frac{50}{200} \times 80 = 20$
$500-800$	$180$	$300$	$\frac{50}{300} \times 180 = 30$

Now,we draw rectangles with lengths as given in the last column. The histogram of the data is shown below.