(B) According to Boyle's law,$PV = \text{constant}$.Taking logarithm on both sides:$\log \ P + \log \ V = \log \ (\text{constant})$$\log \ P = - \log

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Straight line with a negative slope.

(B) According to Boyle's law,$PV = \text{constant}$.Taking logarithm on both sides:$\log \ P + \log \ V = \log \ (\text{constant})$$\log \ P = - \log \ V + \log \ (\text{constant})$This equation is of the form $y = mx + c$,where $y = \log \ P$,$x = \log \ V$,and the slope $m = -1$.Hence,the plot of $\log \ P$ vs $\log \ V$ is a straight line with a negative slope.

Class 11 Chemistry States of Matter Ideal gas equation and Related gas laws

Medium

For $1 \ mol$ of an ideal gas at a constant temperature $T,$ the plot of $(\log \ P)$ against $(\log \ V)$ is a ($P :$ Pressure,$V:$ Volume)

AIEEE 2012 All AIEEE

A
Straight line parallel to $x-$ axis.
B
Straight line with a negative slope.
C
Curve starting at origin.
D
Straight line passing through origin.

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

States of Matter

Subtopic

Ideal gas equation and Related gas laws

Previous Year

AIEEE 2012 Paper All AIEEE years →

If two moles of an ideal gas at $546 \ K$ occupy a volume of $44.8 \ L$,the pressure must be ............. $atm$.

Easy

View Solution

What is the new temperature of a gas when its initial volume $3 \ dm^3$ at $300 \ K$ is doubled at constant pressure (in $K$)?

MediumMHT CET 2023

View Solution

The following $P$ vs $V$ curve is plotted. What is the relation between $T_1$,$T_2$ and $T_3$?

Medium

View Solution

At what temperature $K$ will the kinetic energy of $0.3 \ mol$ of $He$ be equal to the kinetic energy of $0.4 \ mol$ of $Ar$ at $400 \ K$?

Medium

View Solution

How many times the volume of a diatomic gas should be increased reversibly and adiabatically in order to reduce its $RMS$ velocity to half of its initial value?

DifficultTS EAMCET 2021

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

For $1 \ mol$ of an ideal gas at a constant temperature $T,$ the plot of $(\log \ P)$ against $(\log \ V)$ is a ($P :$ Pressure,$V:$ Volume)

Similar Questions

If two moles of an ideal gas at $546 \ K$ occupy a volume of $44.8 \ L$,the pressure must be ............. $atm$.

What is the new temperature of a gas when its initial volume $3 \ dm^3$ at $300 \ K$ is doubled at constant pressure (in $K$)?

The following $P$ vs $V$ curve is plotted. What is the relation between $T_1$,$T_2$ and $T_3$?

At what temperature $K$ will the kinetic energy of $0.3 \ mol$ of $He$ be equal to the kinetic energy of $0.4 \ mol$ of $Ar$ at $400 \ K$?

How many times the volume of a diatomic gas should be increased reversibly and adiabatically in order to reduce its $RMS$ velocity to half of its initial value?

Vedclass Test Series

Exam Paper Generator

Online Exam Module