For 0

Question

(B) In the interval $0^{\circ} < 	heta < 90^{\circ}$:$1$. The value of $\sin 	heta$ increases from $0$ to $1$ as $	heta$ increases from $0^{\circ}$

Vedclass · Accepted Answer

$\sin 	heta$

Vedclass · Answer

(B) In the interval $0^{\circ} $1$. The value of $\sin 	heta$ increases from $0$ to $1$ as $	heta$ increases from $0^{\circ}$ to $90^{\circ}$.$2$. The value of $\cos 	heta$ decreases from $1$ to $0$ as $	heta$ increases from $0^{\circ}$ to $90^{\circ}$.$3$. The value of $\operatorname{cosec} 	heta$ decreases from $\infty$ to $1$ as $	heta$ increases from $0^{\circ}$ to $90^{\circ}$.$4$. The value of $\cot 	heta$ decreases from $\infty$ to $0$ as $	heta$ increases from $0^{\circ}$ to $90^{\circ}$.Therefore,the only trigonometric function among the options that increases as $	heta$ increases is $\sin 	heta$.

For $0 < \theta < 90^{\circ},$ the value of $\ldots \ldots \ldots \ldots$ increases as $\theta$ increases from $0^{\circ}$ to $90^{\circ}$.

Similar Questions

For acute angles $A$ and $B,$ if $\tan A = 1$ and $\sin B = \frac{1}{\sqrt{2}},$ then $\cos (A + B) = \dots$

Write 'True' or 'False' and justify your answer.
The value of $2 \sin \theta$ can be $(a + \frac{1}{a}),$ where $a$ is a positive number,and $a \neq 1$.

Write 'True' or 'False' and justify your answer.
The value of the expression $(\sin 80^{\circ} - \cos 80^{\circ})$ is negative.

If $\tan 7 \theta \cdot \tan 3 \theta = 1,$ then the value of $\theta$ is ..........

$\cos (40^{\circ}-\theta)-\sin (50^{\circ}+\theta) = \ldots \ldots \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module