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(A) Given $A = \begin{bmatrix} 0 & 0 & 3 \ 0 & 3 & 0 \ 3 & 0 & 0 \end{bmatrix}$.First,we calculate $A^2 = A 	imes A$:$A^2 = \begin{bmatrix} 0 & 0 &

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$A^2 = 9I_3$

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(A) Given $A = \begin{bmatrix} 0 & 0 & 3 \ 0 & 3 & 0 \ 3 & 0 & 0 \end{bmatrix}$.First,we calculate $A^2 = A 	imes A$:$A^2 = \begin{bmatrix} 0 & 0 & 3 \ 0 & 3 & 0 \ 3 & 0 & 0 \end{bmatrix} \begin{bmatrix} 0 & 0 & 3 \ 0 & 3 & 0 \ 3 & 0 & 0 \end{bmatrix}$$A^2 = \begin{bmatrix} (0)(0)+(0)(0)+(3)(3) & (0)(0)+(0)(3)+(3)(0) & (0)(3)+(0)(0)+(3)(0) \ (0)(0)+(3)(0)+(0)(3) & (0)(0)+(3)(3)+(0)(0) & (0)(3)+(3)(0)+(0)(0) \ (3)(0)+(0)(0)+(0)(3) & (3)(0)+(0)(3)+(0)(0) & (3)(3)+(0)(0)+(0)(0) \end{bmatrix}$$A^2 = \begin{bmatrix} 9 & 0 & 0 \ 0 & 9 & 0 \ 0 & 0 & 9 \end{bmatrix} = 9 \begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix} = 9I_3$.Thus,the correct statement is $A^2 = 9I_3$.

For $A = \begin{bmatrix} 0 & 0 & 3 \\ 0 & 3 & 0 \\ 3 & 0 & 0 \end{bmatrix}$,which statement is correct?

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