For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2 \, k\Omega$ is $4 \, V$. If the current amplification factor $(\beta)$ of the transistor is $100$ and the base resistance is $1 \, k\Omega$,then the input signal voltage is ....... $mV$.

$A$ transistor is operating in the active mode. $v_1$ is the potential barrier across the base-emitter junction and $v_2$ is the potential barrier across the collector-base junction. $b_1$ is the width of the depletion layer of the base-emitter junction and $b_2$ is the width of the collector-base junction.

The phase difference between the input voltage and the output voltage in a common emitter amplifier is (in $^{\circ}$)

An oscillator is nothing but an amplifier with

If the base current is $100 \mu A$ and the collector current is $3 \ mA$,then the values of $\beta$,$\alpha$,and $I_e$ are respectively:

For a given transistor amplifier circuit in $CE$ configuration with $V_{CC} = 1 \text{ V}$,$R_c = 1 \text{ k}\Omega$,$R_b = 100 \text{ k}\Omega$,and $\beta = 100$,the value of the base current $I_b$ is: