For CH_3Br + OH^{-} rightarrow CH_3OH + Br^{- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction $CH_3Br + OH^{-} \rightarrow CH_3OH + Br^{-}$ proceeds through an $S_N2$ mechanism.In an $S_N2$ reaction,the rate-determining step in

Vedclass · Accepted Answer

rate $= k[CH_3Br][OH^{-}]$

Vedclass · Answer

(C) The reaction $CH_3Br + OH^{-} \rightarrow CH_3OH + Br^{-}$ proceeds through an $S_N2$ mechanism.In an $S_N2$ reaction,the rate-determining step involves both the substrate and the nucleophile.Therefore,the rate law is given by the expression $rate = k[CH_3Br][OH^{-}]$.This is a second-order reaction where the rate depends on the concentration of both the methyl bromide and the hydroxide ion.

For $CH_3Br + OH^{-} \rightarrow CH_3OH + Br^{-}$ the rate of reaction is given by the expression:

Similar Questions

The major product in the given reaction is:

Select the correct decreasing order of boiling points of compounds from the following.

The decreasing order of reactivity towards $S_N 1$ reaction for the following compounds is:

Which one among the following undergoes dehydrohalogenation most readily?

The $S_N2$ product of the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module