For a NAND gate, the inputs and outputs are g | vedclass

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(B) The Boolean expression for a $NAND$ gate is $Y = \overline{A \cdot B}$.$1$. For $A = 0, B = 1$: $Y = \overline{0 \cdot 1} = \overline{0} = 1$. Thu

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$1, 1, 1, 0$

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(B) The Boolean expression for a $NAND$ gate is $Y = \overline{A \cdot B}$.$1$. For $A = 0, B = 1$: $Y = \overline{0 \cdot 1} = \overline{0} = 1$. Thus, $C = 1$.$2$. For $A = 0, B = 0$: $Y = \overline{0 \cdot 0} = \overline{0} = 1$. Thus, $D = 1$.$3$. For $A = 1, B = 0$: $Y = \overline{1 \cdot 0} = \overline{0} = 1$. Thus, $E = 1$.$4$. For $A = 1, B = 1$: $Y = \overline{1 \cdot 1} = \overline{1} = 0$. Thus, $F = 0$.Therefore, the values are $C = 1, D = 1, E = 1, F = 0$.

Input $A$	Input $B$	Output $Y$
$0$	$1$	$C$
$0$	$0$	$D$
$1$	$0$	$E$
$1$	$1$	$F$

For a $NAND$ gate, the inputs and outputs are given in the table below. The values taken by $C, D, E, F$ are respectively:
Input $A$ Input $B$ Output $Y$
$0$ $1$ $C$
$0$ $0$ $D$
$1$ $0$ $E$
$1$ $1$ $F$

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For a $NAND$ gate, the inputs and outputs are given in the table below. The values taken by $C, D, E, F$ are respectively:Input $A$Input $B$Output $Y$$0$$1$$C$$0$$0$$D$$1$$0$$E$$1$$1$$F$