For a p-block element,its 3d, 3s, 3p and 4s o | vedclass

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Question

(C) The electronic configuration of the element is given by filling the orbitals in the order: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^{10}, 4p^{1-6}$

Vedclass · Accepted Answer

$31 - 36$

Vedclass · Answer

(C) The electronic configuration of the element is given by filling the orbitals in the order: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^{10}, 4p^{1-6}$.Summing the electrons: $2+2+6+2+6+2+10 = 30$ electrons are filled before the $4p$ orbital.For a $p$-block element,the differentiating electron enters the $4p$ orbital.If the $4p$ orbital has $1$ electron,the atomic number is $30 + 1 = 31$ (Gallium,$Ga$).If the $4p$ orbital has $6$ electrons,the atomic number is $30 + 6 = 36$ (Krypton,$Kr$).Thus,the range of atomic numbers for this configuration is $31 - 36$.

Column $I$	Column $II$
$A$. $Bi^{3+} \longrightarrow (BiO)^{+}$	$P$. Heat
$B$. $[AlO_2]^{-} \longrightarrow Al(OH)_3$	$Q$. Hydrolysis
$C$. $SiO_4^{4-} \longrightarrow Si_2O_7^{6-}$	$R$. Acidification
$D$. $(B_4O_7^{2-}) \longrightarrow [B(OH)_3]$	$S$. Dilution by water

For a $p$-block element,its $3d, 3s, 3p$ and $4s$ orbitals are completely filled and the differentiating electron goes to the $4p$ orbital. The element should have its atomic number in the range:

Similar Questions

Match the following:

Column $I$ Column $II$

$A$. $Bi^{3+} \longrightarrow (BiO)^{+}$ $P$. Heat

$B$. $[AlO_2]^{-} \longrightarrow Al(OH)_3$ $Q$. Hydrolysis

$C$. $SiO_4^{4-} \longrightarrow Si_2O_7^{6-}$ $R$. Acidification

$D$. $(B_4O_7^{2-}) \longrightarrow [B(OH)_3]$ $S$. Dilution by water

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