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(C) In a compound microscope,the objective lens forms a real,inverted,and magnified image of the object,which acts as an object for the eyepiece.To ac

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${f_o} < {f_e}$

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(C) In a compound microscope,the objective lens forms a real,inverted,and magnified image of the object,which acts as an object for the eyepiece.To achieve high magnification,the objective lens must have a very short focal length $({f_o})$ so that it can be placed close to the object.The eyepiece acts as a simple magnifier and typically has a focal length $({f_e})$ that is larger than the focal length of the objective lens.Therefore,for a compound microscope to function effectively with high magnification,the condition is ${f_o} < {f_e}$.

For a compound microscope,the focal lengths of the objective lens and the eye lens are ${f_o}$ and ${f_e}$ respectively. The microscope provides magnification when:

Similar Questions

In a compound microscope,the focal length of the objective lens is $1.2 \, cm$ and the focal length of the eyepiece is $3.0 \, cm$. When the object is kept at $1.25 \, cm$ in front of the objective,the final image is formed at infinity. The magnifying power of the compound microscope is:

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Mention the maximum magnification of a simple microscope.

To improve the resolving power of a compound microscope, we should:

In a simple microscope,if the final image is formed at infinity,what will be its magnifying power?

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