For a concave mirror,if a real image is forme | vedclass

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(A) The mirror formula is given by $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Rearranging this to express $\frac{1}{v}$ in terms of $\frac{1}{u}$,we ge

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(A) The mirror formula is given by $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Rearranging this to express $\frac{1}{v}$ in terms of $\frac{1}{u}$,we get $\frac{1}{v} = -\frac{1}{u} + \frac{1}{f}$.This equation is of the linear form $y = mx + c$,where $y = \frac{1}{v}$,$x = \frac{1}{u}$,slope $m = -1$,and intercept $c = \frac{1}{f}$.For a concave mirror,the focal length $f$ is negative,so $c = \frac{1}{f}$ is negative. However,for a real image,$u$ and $v$ are both negative. As $u$ varies from $f$ to $\infty$,$v$ varies from $\infty$ to $f$. The graph is a straight line with a slope of $-1$ and a negative intercept on both axes,which corresponds to the form shown in option $A$.

For a concave mirror,if a real image is formed,the graph between $\frac{1}{u}$ and $\frac{1}{v}$ is of the form:

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