For a first order reaction $A \rightarrow P$,the temperature $(T)$ dependent rate constant $(k)$ was found to follow the equation $\log k = -(2000) \frac{1}{T} + 6.0$. The pre-exponential factor $A$ and the activation energy $E_{a}$,respectively,are

  • A
    $1.0 \times 10^6 \ s^{-1}$ and $9.2 \ kJ \ mol^{-1}$
  • B
    $6.0 \ s^{-1}$ and $16.6 \ kJ \ mol^{-1}$
  • C
    $1.0 \times 10^6 \ s^{-1}$ and $16.6 \ kJ \ mol^{-1}$
  • D
    $1.0 \times 10^6 \ s^{-1}$ and $38.3 \ kJ \ mol^{-1}$

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Explain the effect of an increase in temperature on the rate of reaction and the rate constant.

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Write the logarithmic form of the Arrhenius equation $k = A e^{-\frac{E_a}{RT}}$.

The number of given statement/s which is/are correct is $.....$.
$(A)$ The stronger the temperature dependence of the rate constant,the higher is the activation energy.
$(B)$ If a reaction has zero activation energy,its rate is independent of temperature.
$(C)$ The stronger the temperature dependence of the rate constant,the smaller is the activation energy.
$(D)$ If there is no correlation between the temperature and the rate constant then it means that the reaction has negative activation energy.

$A_{(g)} + B_{(g)} \rightleftharpoons C_{(g)} + D_{(g)}$
The curves $M$ and $N$ represent the variation of energy with reaction coordinate for the reaction in absence and presence of catalyst.
Which value represents the activation energy $(E_a)$ for the backward reaction in the presence of catalyst?

For a certain gaseous reaction,the temperature is increased by $10\,^{\circ}C$ from $25\,^{\circ}C$ to $35\,^{\circ}C$. If the rate of the reaction doubles,what will be the value of the activation energy $(E_a)$?

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