For a first order reaction,the velocity const | vedclass

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(C) For a first order reaction,the rate constant $k$ is given by the formula: $k = \frac{2.303}{t} \log \frac{a}{a - x}$ Given $k = 10^{-3} \ s^{-1}$

Vedclass · Accepted Answer

$1100$

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(C) For a first order reaction,the rate constant $k$ is given by the formula: $k = \frac{2.303}{t} \log \frac{a}{a - x}$ Given $k = 10^{-3} \ s^{-1}$ and $x = \frac{2}{3}a$,the remaining concentration is $a - x = a - \frac{2}{3}a = \frac{1}{3}a$. Substituting these values into the equation: $10^{-3} = \frac{2.303}{t} \log \frac{a}{a/3}$ $10^{-3} = \frac{2.303}{t} \log 3$ Using $\log 3 \approx 0.4771$: $10^{-3} = \frac{2.303 	imes 0.4771}{t}$ $t = \frac{2.303 	imes 0.4771}{10^{-3}} \approx 1099.16 \ s \approx 1100 \ s$.

For a first order reaction,the velocity constant is $K = 10^{-3} \ s^{-1}$. The two-third life for it would be ........... $s$.

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