For a given electromagnetic wave,the magnitude of the electric field is $6.6 \,V \,m^{-1}$ at a point in space. The magnitude of the magnetic field at this point is . . . . . . $T$.

For an electromagnetic wave propagating through vacuum, $\vec{k}$, $\vec{E}$, and $\omega$ represent the propagation vector, electric field, and angular frequency, respectively. The magnetic field associated with this wave is represented by:

Write the equation for the energy density of electromagnetic waves.

In an electromagnetic wave,if $\overrightarrow{E}$ is the electric field and $\overrightarrow{B}$ is the magnetic field,then the direction of propagation of the wave is given by:

$A$ plane electromagnetic wave of frequency $25 \text{ MHz}$ travels in free space along the $X$-direction. At a particular point in space and time,the magnetic field is $\overrightarrow{B} = 2.1 \times 10^{-8} \hat{k} \text{ T}$. Find the electric field $\overrightarrow{E}$ at this point.

The oscillating magnetic field in a plane electromagnetic wave is given by $B_{y} = 5 \times 10^{-6} \sin(1000\pi(5x - 4 \times 10^{8}t)) \text{ T}$. The amplitude of the electric field will be: