For a given frequency distribution,n=100, A=1 | vedclass

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(B) The formula for the mean using the assumed mean method is given by: $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{n}$.Given values are $n = 100$,$A = 1

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$0$

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(B) The formula for the mean using the assumed mean method is given by: $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{n}$.Given values are $n = 100$,$A = 15$,and $\bar{x} = 15$.Substituting these values into the formula:$15 = 15 + \frac{\Sigma f_{i} d_{i}}{100}$.Subtracting $15$ from both sides:$15 - 15 = \frac{\Sigma f_{i} d_{i}}{100}$.$0 = \frac{\Sigma f_{i} d_{i}}{100}$.Multiplying both sides by $100$,we get:$\Sigma f_{i} d_{i} = 0$.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$2$	$6$	$8$	$16$	$20$	$18$	$16$	$14$

Class	$11-13$	$13-15$	$15-17$	$17-19$	$19-21$	$21-23$	$23-25$
Frequency	$3$	$6$	$9$	$13$	$f$	$5$	$4$

For a given frequency distribution,$n=100, A=15$ and $\bar{x}=15$. Then,$\Sigma f_{i} d_{i} = \ldots$

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