For a given frequency distribution,$n=100$ and $\Sigma f_{i} x_{i}=245$. Then,$\bar{x}=\ldots \ldots \ldots \ldots$
- A$24.5$
- B$2.45$
- C$145$
- D$1.45$
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If mode $= 25$ and mean $= 19,$ then median $= \dots$
Medium
View SolutionWeekly income of $600$ families is tabulated below:
Weekly income Number of families $0-1000$ $250$ $1000-2000$ $190$ $2000-3000$ $100$ $3000-4000$ $40$ $4000-5000$ $15$ $5000-6000$ $5$ Total $600$
Compute the median income (in $Rs.$).
| Weekly income | Number of families |
| $0-1000$ | $250$ |
| $1000-2000$ | $190$ |
| $2000-3000$ | $100$ |
| $3000-4000$ | $40$ |
| $4000-5000$ | $15$ |
| $5000-6000$ | $5$ |
| Total | $600$ |
Compute the median income (in $Rs.$).
Medium
View SolutionThe mean of the following frequency distribution is $18$. Find the missing frequency $f$.
Class $11-13$ $13-15$ $15-17$ $17-19$ $19-21$ $21-23$ $23-25$ Frequency $3$ $6$ $9$ $13$ $f$ $5$ $4$
| Class | $11-13$ | $13-15$ | $15-17$ | $17-19$ | $19-21$ | $21-23$ | $23-25$ |
| Frequency | $3$ | $6$ | $9$ | $13$ | $f$ | $5$ | $4$ |
Medium
View SolutionConstruct the cumulative frequency distribution of the following distribution:
Class $12.5-17.5$ $17.5-22.5$ $22.5-27.5$ $27.5-32.5$ $32.5-37.5$ Frequency $2$ $22$ $19$ $14$ $13$
| Class | $12.5-17.5$ | $17.5-22.5$ | $22.5-27.5$ | $27.5-32.5$ | $32.5-37.5$ |
| Frequency | $2$ | $22$ | $19$ | $14$ | $13$ |
Medium
View SolutionIn the formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$,$x_{i}$ represents ..........
Easy
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