For a given frequency distribution,bar{x} = 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The formula for the mean using the assumed mean method is given by: $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{n}$.Given values are $\bar{x} = 19.7$

Vedclass · Accepted Answer

$-15$

Vedclass · Answer

(A) The formula for the mean using the assumed mean method is given by: $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{n}$.Given values are $\bar{x} = 19.7$,$A = 20$,and $n = 50$.Substituting these values into the formula:$19.7 = 20 + \frac{\Sigma f_{i} d_{i}}{50}$.Subtracting $20$ from both sides:$19.7 - 20 = \frac{\Sigma f_{i} d_{i}}{50}$.$-0.3 = \frac{\Sigma f_{i} d_{i}}{50}$.Multiplying both sides by $50$:$\Sigma f_{i} d_{i} = -0.3 	imes 50$.$\Sigma f_{i} d_{i} = -15$.

Class	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$3$	$x$	$7$	$7$	$y$

Class	$60-70$	$70-80$	$80-90$	$90-100$	$100-110$	$110-120$
Frequency	$5$	$15$	$20$	$30$	$20$	$8$

For a given frequency distribution,$\bar{x} = 19.7$,$A = 20$,and $n = 50$. Then,$\Sigma f_{i} d_{i} = \ldots$

Similar Questions

The mean of the following data is $55.5$ and the total frequency is $20$. Find the missing frequencies $x$ and $y$.
Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
Frequency $3$ $x$ $7$ $7$ $y$

For a given frequency distribution,$\Sigma f_{i} u_{i} = -13$,$n = \Sigma f_{i} = 100$,$A = 62.5$ and $c = 15$. Then,mean $\bar{x} = \dots$

Find the median of the following frequency distribution:

Class $60-70$ $70-80$ $80-90$ $90-100$ $100-110$ $110-120$

Frequency $5$ $15$ $20$ $30$ $20$ $8$

In the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$,$u_{i} =$ .........

While computing the mean of grouped data,we assume that the frequencies are

Vedclass Test Series

Exam Paper Generator

Online Exam Module