For a given material,the Young's modulus is 2 | vedclass

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(D) The relationship between Young's modulus $(Y)$,rigidity modulus $(\eta)$,and Poisson's ratio $(\sigma)$ is given by the formula: $Y = 2\eta(1 + \s

Vedclass · Accepted Answer

$0.2$

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(D) The relationship between Young's modulus $(Y)$,rigidity modulus $(\eta)$,and Poisson's ratio $(\sigma)$ is given by the formula: $Y = 2\eta(1 + \sigma)$.Given that the Young's modulus is $2.4$ times the rigidity modulus,we have $Y = 2.4\eta$.Substituting this into the formula: $2.4\eta = 2\eta(1 + \sigma)$.Dividing both sides by $2\eta$,we get $1.2 = 1 + \sigma$.Solving for $\sigma$,we find $\sigma = 1.2 - 1 = 0.2$.

For a given material,the Young's modulus is $2.4$ times that of the rigidity modulus. Its Poisson's ratio is

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