For a reversible spontaneous change,Delta S i | vedclass

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(C) For a reversible process,the change in entropy is defined by the relation $dS = \frac{dq_{rev}}{T}$.Integrating this expression for a finite chang

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$\frac{q}{T}$

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(C) For a reversible process,the change in entropy is defined by the relation $dS = \frac{dq_{rev}}{T}$.Integrating this expression for a finite change,we get $\Delta S = \int \frac{dq_{rev}}{T}$.Since $T$ is constant for an isothermal reversible process,$\Delta S = \frac{1}{T} \int dq_{rev}$.As $\int dq_{rev} = q$,the expression becomes $\Delta S = \frac{q}{T}$.

For a reversible spontaneous change,$\Delta S$ is:

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