For a transistor,the current ratio $\beta_{dc}$ is defined as the ratio of:

In a $p-n-p$ transistor working as a common base amplifier, when the current gain is $0.96$ and emitter current is $7.2 \,mA$, the base current is (in $\,mA$)

In a transistor $(\beta=50)$,the voltage across $5 \, k\Omega$ load resistance in the collector circuit is $5 \, V$. The base current is ......... $mA$.

What is the power gain in a $CE$ amplifier,where the input resistance is $3\,k\Omega$ and the load resistance is $24\,k\Omega$,given $\beta = 20$?

For a common base configuration of a $PNP$ transistor,$\frac{I_C}{I_E} = 0.96$. Then,the maximum current gain in common emitter configuration will be:

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is