For an electron with n = 3,there is only one | vedclass

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(C) The number of radial nodes is given by the formula: $	ext{Radial nodes} = n - \ell - 1$.Given $n = 3$ and $	ext{Radial nodes} = 1$,we have: $3 -

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$\sqrt{2} \frac{h}{2\pi}$

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(C) The number of radial nodes is given by the formula: $	ext{Radial nodes} = n - \ell - 1$.Given $n = 3$ and $	ext{Radial nodes} = 1$,we have: $3 - \ell - 1 = 1$.Solving for $\ell$: $2 - \ell = 1$,which gives $\ell = 1$.An orbital with $\ell = 1$ is a $p$-orbital.The formula for orbital angular momentum is $\sqrt{\ell(\ell + 1)} \frac{h}{2\pi}$.Substituting $\ell = 1$: $\sqrt{1(1 + 1)} \frac{h}{2\pi} = \sqrt{2} \frac{h}{2\pi}$.

For an electron with $n = 3$,there is only one radial node. The orbital angular momentum of the electron will be

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