For an electron with $n = 3$,there is only one radial node. The orbital angular momentum of the electron will be

  • A
    $0$
  • B
    $\sqrt{6} \frac{h}{2\pi}$
  • C
    $\sqrt{2} \frac{h}{2\pi}$
  • D
    $3 \left(\frac{h}{2\pi}\right)$

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Similar Questions

Identify the impossible quantum number set for an electron from the following:

Match the entries in Column $I$ with the correctly related quantum number$(s)$ in Column $II$.
Column $I$ Column $II$
$A$. Orbital angular momentum of the electron in a hydrogen-like atomic orbital $p$. Principal quantum number
$B$. $A$ hydrogen-like one-electron wave function obeying Pauli principle $q$. Azimuthal quantum number
$C$. Shape,size and orientation of hydrogen-like atomic orbitals $r$. Magnetic quantum number
$D$. Probability density of electron at the nucleus in hydrogen-like atom $s$. Electron spin quantum number

The magnetic quantum number specifies

What is the total number of unpaired electrons in an element placed at period-$4$ and group-$12$ either in excited or at ground state?

What is the number of unpaired electrons in the electronic configuration of the $N^{+2}$ ion?

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