For an octahedral complex,which of the follow | vedclass

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Question

(A) The Crystal Field Stabilization Energy $(CFSE)$ for an octahedral complex is calculated as $CFSE = [n(t_{2g}) 	imes (-0.4 \Delta_{o}) + n(e_{g})

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Low spin $d^{5}$

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(A) The Crystal Field Stabilization Energy $(CFSE)$ for an octahedral complex is calculated as $CFSE = [n(t_{2g}) 	imes (-0.4 \Delta_{o}) + n(e_{g}) 	imes (0.6 \Delta_{o})]$.For Low spin $d^{5}$: $t_{2g}^{5} e_{g}^{0}$,$CFSE = 5(-0.4 \Delta_{o}) + 0(0.6 \Delta_{o}) = -2.0 \Delta_{o}$.For Low spin $d^{4}$: $t_{2g}^{4} e_{g}^{0}$,$CFSE = 4(-0.4 \Delta_{o}) + 0(0.6 \Delta_{o}) = -1.6 \Delta_{o}$.For High spin $d^{7}$: $t_{2g}^{5} e_{g}^{2}$,$CFSE = 5(-0.4 \Delta_{o}) + 2(0.6 \Delta_{o}) = -2.0 + 1.2 = -0.8 \Delta_{o}$.For High spin $d^{6}$: $t_{2g}^{4} e_{g}^{2}$,$CFSE = 4(-0.4 \Delta_{o}) + 2(0.6 \Delta_{o}) = -1.6 + 1.2 = -0.4 \Delta_{o}$.Comparing the magnitudes,the Low spin $d^{5}$ configuration gives the maximum magnitude of $2.0 \Delta_{o}$.

For an octahedral complex,which of the following $d-$electronic configuration will give the maximum magnitude of crystal field stabilization energy,in terms of $\Delta_{o}$?

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Choose the correct answer from the given below:

The correct order of the complexes $[Co(NH_3)_5(H_2O)]^{3+}$ $(A)$,$[Co(NH_3)_6]^{3+}$ $(B)$,$[Co(CN)_6]^{3-}$ $(C)$,and $[CoCl(NH_3)_5]^{2+}$ $(D)$ in terms of the wavelength of light absorbed is:

What is the correct order of increasing field strength for the ligands $NH_3$,$en$,$CN^-$,and $CO$?

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