For each of the following $A.P.s$,find the $n^{th}$ term: $27, 22, 17, 12, \ldots$
(N/A) The given arithmetic progression is $27, 22, 17, 12, \ldots$
Here,the first term $a = 27$.
The common difference $d = 22 - 27 = -5$.
The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.
Substituting the values,we get $T_n = 27 + (n - 1)(-5)$.
$T_n = 27 - 5n + 5$.
$T_n = -5n + 32$.
Here,the first term $a = 27$.
The common difference $d = 22 - 27 = -5$.
The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.
Substituting the values,we get $T_n = 27 + (n - 1)(-5)$.
$T_n = 27 - 5n + 5$.
$T_n = -5n + 32$.
Explore More
Similar Questions
The sum of how many terms of the $A.P.$ $9, 17, 25, \ldots$ is $636$?
Easy
View SolutionFind the sum of the last ten terms of the $AP: 8, 10, 12, \ldots, 126$.
Difficult
View SolutionCan any term of the $A.P.$ $14, 18, 22, \ldots$ be $142$? If yes,which term?
Medium
View SolutionFind the $12^{th}$ term and the $24^{th}$ term of the $A.P.$ $9, 13, 17, \ldots$
Medium
View SolutionIf the sum of the first $6$ terms of an $AP$ is $36$ and that of the first $16$ terms is $256,$ find the sum of the first $10$ terms.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo