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Question

(C) Let $x = 0.3\overline{6} = 0.3666...$ (Equation $1$)Multiply both sides by $10$: $10x = 3.666...$ (Equation $2$)Multiply Equation $1$ by $100$: $1

Vedclass · Accepted Answer

$\frac{11}{30}$

Vedclass · Answer

(C) Let $x = 0.3\overline{6} = 0.3666...$ (Equation $1$)Multiply both sides by $10$: $10x = 3.666...$ (Equation $2$)Multiply Equation $1$ by $100$: $100x = 36.666...$ (Equation $3$)Subtract Equation $2$ from Equation $3$:$100x - 10x = 36.666... - 3.666...$$90x = 33$$x = \frac{33}{90}$Simplify the fraction by dividing both numerator and denominator by $3$:$x = \frac{11}{30}$

For each question,select the proper option from four options given,to make the statement true: $0.3\overline{6}=$

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