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(A) The Freundlich adsorption isotherm equation is given by $\frac{x}{m} = K P^{1/n}$.Taking logarithm on both sides,we get $\log \left( \frac{x}{m} \

Vedclass · Accepted Answer

$48$

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(A) The Freundlich adsorption isotherm equation is given by $\frac{x}{m} = K P^{1/n}$.Taking logarithm on both sides,we get $\log \left( \frac{x}{m} ight) = \frac{1}{n} \log P + \log K$.Comparing this with the equation of a straight line $y = mx + c$,the slope is $\frac{1}{n} = 2$ and the intercept is $\log K = 0.4771$.Since $\log 3 = 0.4771$,we find $K = 3$.Now,substituting the values $K = 3$,$P = 0.04 \ atm$,and $n = 0.5$ (since $\frac{1}{n} = 2$) into the equation $\frac{x}{m} = K P^{1/n}$:$\frac{x}{m} = 3 	imes (0.04)^{2} = 3 	imes 0.0016 = 0.0048 \ g$.Converting this to the required format: $0.0048 \ g = 48 	imes 10^{-4} \ g$.

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