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Question

(B) The magnifying power $(m)$ of an astronomical telescope in normal adjustment is given by the formula: $m = -f_o / f_e$, where $f_o$ is the focal l

Vedclass · Accepted Answer

The focal length of the objective must be large.

Vedclass · Answer

(B) The magnifying power $(m)$ of an astronomical telescope in normal adjustment is given by the formula: $m = -f_o / f_e$, where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.To obtain a large magnifying power $(m)$, the numerator $(f_o)$ must be large and the denominator $(f_e)$ must be small.Therefore, the focal length of the objective lens should be large.

For large magnifying power of a telescope, which of the following conditions is required?

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