For nuclei with mass number close to 119 and | vedclass

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Question

(A) The binding energy per nucleon $(BE/A)$ for a nucleus of mass number $A = 238$ is $7.6 	ext{ MeV}$, and for a nucleus of mass number $A = 119$, i

Vedclass · Accepted Answer

$214$

Vedclass · Answer

(A) The binding energy per nucleon $(BE/A)$ for a nucleus of mass number $A = 238$ is $7.6 	ext{ MeV}$, and for a nucleus of mass number $A = 119$, it is $8.6 	ext{ MeV}$.Total binding energy of the parent nucleus $(A = 238)$ is $E_1 = 238 	imes 7.6 	ext{ MeV} = 1808.8 	ext{ MeV}$.When the nucleus splits into two fragments of mass number $119$ each, the total binding energy of the product nuclei is $E_2 = 2 	imes (119 	imes 8.6 	ext{ MeV}) = 238 	imes 8.6 	ext{ MeV} = 2046.8 	ext{ MeV}$.The energy released in the fission process is $\Delta E = E_2 - E_1 = 2046.8 	ext{ MeV} - 1808.8 	ext{ MeV} = 238 	ext{ MeV}$.Among the given options, $214 	ext{ MeV}$ is the closest approximate value.

Similar Questions

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