For the reaction: SO_{2(g)} + frac{1}{2} O_{2 | vedclass

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(D) The relationship between $K_P$ and $K_C$ is given by the equation: $K_P = K_C(RT)^{\Delta n_g}$.For the reaction $SO_{2(g)} + \frac{1}{2} O_{2(g)}

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(D) The relationship between $K_P$ and $K_C$ is given by the equation: $K_P = K_C(RT)^{\Delta n_g}$.For the reaction $SO_{2(g)} + \frac{1}{2} O_{2(g)} ightleftharpoons SO_{3(g)}$,the change in the number of moles of gaseous species is $\Delta n_g = 1 - (1 + 0.5) = -0.5$.Given $T = 27^{\circ} C = 300 \ K$,$R = 0.082 \ L \ atm \ K^{-1} \ mol^{-1}$,and $K_P = 2 	imes 10^{12}$.Substituting the values: $2 	imes 10^{12} = K_C 	imes (0.082 	imes 300)^{-0.5}$.$2 	imes 10^{12} = K_C 	imes (24.6)^{-0.5} = K_C 	imes \frac{1}{\sqrt{24.6}}$.$K_C = 2 	imes 10^{12} 	imes \sqrt{24.6} \approx 2 	imes 10^{12} 	imes 4.96 = 9.92 	imes 10^{12}$.Expressing in terms of $10^{13}$: $K_C = 0.992 	imes 10^{13}$.Rounding to the nearest integer,we get $1 	imes 10^{13}$.

For the reaction: $SO_{2(g)} + \frac{1}{2} O_{2(g)} \rightleftharpoons SO_{3(g)}$,$K_P = 2 \times 10^{12}$ at $27^{\circ} C$ and $1 \ atm$ pressure. The $K_C$ for the same reaction is $......... \times 10^{13}$. (Nearest integer)
(Given $R = 0.082 \ L \ atm \ K^{-1} \ mol^{-1}$)

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For the reaction: $SO_{2(g)} + \frac{1}{2} O_{2(g)} \rightleftharpoons SO_{3(g)}$,$K_P = 2 \times 10^{12}$ at $27^{\circ} C$ and $1 \ atm$ pressure. The $K_C$ for the same reaction is $......... \times 10^{13}$. (Nearest integer)(Given $R = 0.082 \ L \ atm \ K^{-1} \ mol^{-1}$)