For some given data, if $M = 15.4$ and $\bar{x} = 14.5$, then $Z = \dots$
- A$15$
- B$16.2$
- C$13.6$
- D$17.2$
Explore More
Similar Questions
Find the mean of the following data:
Class $200-299$ $300-399$ $400-499$ $500-599$ $600-699$ $700-799$ $800-899$ Frequency $3$ $61$ $118$ $139$ $126$ $151$ $2$
| Class | $200-299$ | $300-399$ | $400-499$ | $500-599$ | $600-699$ | $700-799$ | $800-899$ |
| Frequency | $3$ | $61$ | $118$ | $139$ | $126$ | $151$ | $2$ |
Medium
View SolutionThe mean of the first ten natural numbers is ........
Medium
View SolutionFor the calculations of mode of a grouped data,the maximum frequency of a class is denoted by $\ldots \ldots \ldots . .$
Easy
View SolutionFor a given frequency distribution,$n=200$,$\Sigma f_{i} d_{i}=0$ and $A=25$. Then,$\bar{x}=\ldots \ldots \ldots \ldots$
Easy
View SolutionFor the calculation of mode of the following frequency distribution,$f_{1} = \dots \dots \dots \dots \dots \dots$
Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$ Frequency $12$ $18$ $27$ $20$ $17$ $6$
| Class | $0-100$ | $100-200$ | $200-300$ | $300-400$ | $400-500$ | $500-600$ |
| Frequency | $12$ | $18$ | $27$ | $20$ | $17$ | $6$ |
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo