For the $A.P.$ $-2, -4, -6, \ldots,$ the common difference $d = \ldots$
- A$2$
- B$4$
- C$-2$
- D$-8$
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Similar Questions
In an $AP$,if $a = 1$,$a_{n} = 20$,and $S_{n} = 399$,then $n$ is:
Medium
View SolutionWhich of the following matchings is true for Part $I$ and Part $II$?
Part $I$ Part $II$ $1$. Sixth term of the $A.P.$ $1, 3, 5, 7, \ldots$ $a$. $105$ $2$. Eleventh term of the $A.P.$ $3, 6, 9, 12, \ldots$ $b$. $11$ $3$. Sixteenth term of the $A.P.$ $4, 6, 8, 10, \ldots$ $c$. $33$ $4$. Twenty-first term of the $A.P.$ $5, 10, 15, 20, \ldots$ $d$. $34$
| Part $I$ | Part $II$ |
| $1$. Sixth term of the $A.P.$ $1, 3, 5, 7, \ldots$ | $a$. $105$ |
| $2$. Eleventh term of the $A.P.$ $3, 6, 9, 12, \ldots$ | $b$. $11$ |
| $3$. Sixteenth term of the $A.P.$ $4, 6, 8, 10, \ldots$ | $c$. $33$ |
| $4$. Twenty-first term of the $A.P.$ $5, 10, 15, 20, \ldots$ | $d$. $34$ |
Difficult
View SolutionIf the sum of the first $6$ terms of an $AP$ is $36$ and that of the first $16$ terms is $256,$ find the sum of the first $10$ terms.
Difficult
View SolutionHow many terms of the $AP: -15, -13, -11, \ldots$ are needed to make the sum $-55$? Explain the reason for the double answer.
Medium
View SolutionFind the sum of the first $25$ terms of the $A.P.$ $3, \frac{9}{2}, 6, \frac{15}{2}, \ldots$
Medium
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