For the RC circuit shown,the resistance is R | vedclass

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(D) According to Kirchhoff's voltage law for the $RC$ circuit,the sum of the potential drops across the resistor and the capacitor must equal the elec

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$35$

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(D) According to Kirchhoff's voltage law for the $RC$ circuit,the sum of the potential drops across the resistor and the capacitor must equal the electromotive force of the battery:$V_R + V_C = \xi$Given that the current $I = 0.50 \ A$ and the resistance $R = 10.0 \ \Omega$,the potential drop across the resistor is:$V_R = I 	imes R = 0.50 \ A 	imes 10.0 \ \Omega = 5.0 \ V$Substituting this into the voltage equation:$5.0 \ V + V_C = 12 \ V$$V_C = 12 \ V - 5.0 \ V = 7.0 \ V$The charge $q$ on the capacitor is given by $q = C 	imes V_C$. Given $C = 5.0 \ \mu F$:$q = 5.0 \ \mu F 	imes 7.0 \ V = 35 \ \mu C$Thus,the magnitude of the charge across the capacitor is $35 \ \mu C$.

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