For the calculation of mode of the following | vedclass

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Question

(A) In the given frequency distribution,the maximum frequency is $8$,which corresponds to the class interval $5-7$.Therefore,the modal class is $5-7$.

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) In the given frequency distribution,the maximum frequency is $8$,which corresponds to the class interval $5-7$.Therefore,the modal class is $5-7$.In the formula for mode,$f_{1}$ is the frequency of the modal class,$f_{0}$ is the frequency of the class preceding the modal class,and $f_{2}$ is the frequency of the class succeeding the modal class.Here,the modal class is $5-7$,so its frequency $f_{1} = 8$.The class preceding the modal class is $3-5$,and its frequency is $f_{0} = 3$.Thus,$f_{0} = 3$.

Class	$1-3$	$3-5$	$5-7$	$7-9$	$9-11$
Frequency	$6$	$3$	$8$	$2$	$1$

Class	$4-8$	$8-12$	$12-16$	$16-20$	$20-24$	$24-28$
Frequency	$9$	$8$	$12$	$7$	$15$	$1$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$
Frequency	$7$	$16$	$25$	$32$	$20$

For the calculation of mode of the following frequency distribution,$f_{0} = \dots \dots \dots \dots \dots$

Class $1-3$ $3-5$ $5-7$ $7-9$ $9-11$

Frequency $6$ $3$ $8$ $2$ $1$

Similar Questions

The modal class of the following frequency distribution is ........
Class $4-8$ $8-12$ $12-16$ $16-20$ $20-24$ $24-28$
Frequency $9$ $8$ $12$ $7$ $15$ $1$

For the following data,the modal class is .... .
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$
Frequency $7$ $16$ $25$ $32$ $20$

The formula $\ldots \ldots$ represents the empirical relationship between the measures of central tendency.

For some given data,if $Z + M = 108$ and $Z - M = -6$,then the mean $\bar{x} = \ldots \ldots \ldots$

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For the calculation of mode of the following frequency distribution,$f_{0} = \dots \dots \dots \dots \dots$ Class $1-3$ $3-5$ $5-7$ $7-9$ $9-11$ Frequency $6$ $3$ $8$ $2$ $1$