For the chemical reaction $N_{2(g)} + 3 H_{2(g)} \rightleftharpoons 2 NH_{3(g)}$,the correct option is

  • A
    $-\frac{1}{3} \frac{d[H_{2}]}{dt} = -\frac{1}{2} \frac{d[NH_{3}]}{dt}$
  • B
    $-\frac{d[N_{2}]}{dt} = 2 \frac{d[NH_{3}]}{dt}$
  • C
    $-\frac{d[N_{2}]}{dt} = \frac{1}{2} \frac{d[NH_{3}]}{dt}$
  • D
    $3 \frac{d[H_{2}]}{dt} = 2 \frac{d[NH_{3}]}{dt}$

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