For the circuit shown,which of the following | vedclass

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(D) Initially,the capacitors are charged as $Q_1 = C_1 V_1 = (2\,pF)(30\,V) = 60\,pC$ and $Q_2 = C_2 V_2 = (3\,pF)(20\,V) = 60\,pC$.When switches $S_1

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With $S_1$ and $S_3$ closed,$V_1 = 30\,V, V_2 = 20\,V$

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(D) Initially,the capacitors are charged as $Q_1 = C_1 V_1 = (2\,pF)(30\,V) = 60\,pC$ and $Q_2 = C_2 V_2 = (3\,pF)(20\,V) = 60\,pC$.When switches $S_1$ and $S_3$ are closed,the plates are connected to the ground. The potential difference across $C_1$ remains $30\,V$ (as the left plate is grounded and the right plate is connected to the potential of the junction) and across $C_2$ remains $20\,V$ because the charge on the capacitors remains trapped and unchanged as the circuit is not forming a closed loop with an external source to redistribute charge.Thus,the potential differences $V_1 = 30\,V$ and $V_2 = 20\,V$ remain unchanged.

For the circuit shown,which of the following statements is true?

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