For the complex Cr(CO)_x,find the value of x? | vedclass

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Question

(B) The complex $Cr(CO)_x$ follows the $18$-electron rule for stability in metal carbonyls.$Cr$ (atomic number $24$) has $6$ valence electrons.Each $C

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) The complex $Cr(CO)_x$ follows the $18$-electron rule for stability in metal carbonyls.$Cr$ (atomic number $24$) has $6$ valence electrons.Each $CO$ ligand acts as a $2$-electron donor.According to the $18$-electron rule: $6 + 2x = 18$.$2x = 12$,which gives $x = 6$.Thus,the compound is $Cr(CO)_6$,which is a stable octahedral complex.Hence,the correct option is $(B)$.

For the complex $Cr(CO)_x$,find the value of $x$?

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