For the complex ion [Ni(Cl)_4]^{2-}, what is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. In the complex ion $[Ni(Cl)_4]^{2-}$, the oxidation state of $Ni$ is $+2$. $2$. The electronic configuration of $Ni^{2+}$ $(Z=28)$ is $[Ar] 3

Vedclass · Accepted Answer

$2.83$

Vedclass · Answer

(B) $1$. In the complex ion $[Ni(Cl)_4]^{2-}$, the oxidation state of $Ni$ is $+2$. $2$. The electronic configuration of $Ni^{2+}$ $(Z=28)$ is $[Ar] 3d^8$. $3$. Since $Cl^-$ is a weak field ligand, it does not cause pairing of electrons in the $3d$ orbitals. $4$. The $3d^8$ configuration has two unpaired electrons $(n=2)$. $5$. The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$. $6$. Substituting $n=2$, we get $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \ BM$.

For the complex ion $[Ni(Cl)_4]^{2-}$, what is the theoretical value of the magnetic moment (in $BM$)?

Similar Questions

The pair of complexes $[(C_6H_5)_2Pd(SCN)_2]$ and $[(C_6H_5)_2Pd(NCS)_2]$ represents which type of isomerism?

Which complex possesses a facial $(fac)$ isomer?

The species that can have a $trans$-isomer is: ($en = \text{ethane-}1,2\text{-diamine}$,$ox = \text{oxalate}$)

The magnetic moment of the complex anion $[Cr(NO)(NH_3)(CN)_4]^{2-}$ is $..........$ $B.M.$

Vedclass Test Series

Exam Paper Generator

Online Exam Module