Difficult
For the decomposition of a compound $AB$ at $600 \ K$,the following data were obtained:
$[AB] \ (mol \ dm^{-3})$ Rate of decomposition of $AB \ (mol \ dm^{-3} \ s^{-1})$ $0.20$ $2.75 \times 10^{-8}$ $0.40$ $11.0 \times 10^{-8}$ $0.60$ $24.75 \times 10^{-8}$
The order for the decomposition of $AB$ is:
| $[AB] \ (mol \ dm^{-3})$ | Rate of decomposition of $AB \ (mol \ dm^{-3} \ s^{-1})$ |
| $0.20$ | $2.75 \times 10^{-8}$ |
| $0.40$ | $11.0 \times 10^{-8}$ |
| $0.60$ | $24.75 \times 10^{-8}$ |
The order for the decomposition of $AB$ is:
- A$1.5$
- B$0$
- C$1$
- D$2$
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Similar Questions
For the reaction $X_{2(g)} + Y_{2(g)} \rightarrow 2XY_{(g)}$,the following data are observed:
$[X_{2}] \ (M)$ $[Y_{2}] \ (M)$ Rate of appearance of $XY \ (M \ sec^{-1})$ $0.1$ $0.1$ $5 \times 10^{-6}$ $0.2$ $0.1$ $10^{-5}$ $0.2$ $0.2$ $4 \times 10^{-5}$
Calculate the rate constant of the reaction (in $M^{1-n} \ sec^{-1}$),where $n$ is the order of the reaction.
| $[X_{2}] \ (M)$ | $[Y_{2}] \ (M)$ | Rate of appearance of $XY \ (M \ sec^{-1})$ |
| $0.1$ | $0.1$ | $5 \times 10^{-6}$ |
| $0.2$ | $0.1$ | $10^{-5}$ |
| $0.2$ | $0.2$ | $4 \times 10^{-5}$ |
Calculate the rate constant of the reaction (in $M^{1-n} \ sec^{-1}$),where $n$ is the order of the reaction.
Difficult
View SolutionWhat is the relationship between the half-life period $(t_{1/2})$ and the initial concentration $([R]_0)$ for a reaction of order $n$?
Medium
View SolutionRate law for the reaction,$C_2H_5I_{(g)} \rightarrow C_2H_{4_{(g)}} + HI_{(g)}$ is $r = k[C_2H_5I]$. What is the order and molecularity of this reaction?
For a reaction $A \rightarrow 2 B + C$ the half-lives are $100 \ s$ and $50 \ s$ when the concentration of reactant $A$ is $0.5 \ mol \ L^{-1}$ and $1.0 \ mol \ L^{-1}$ respectively. The order of the reaction is (Nearest Integer).
The given plots represent the variation of the concentration of a reactant $R$ with time for two different reactions $(i)$ and $(ii).$ The respective orders of the reactions are
DifficultJEE MAIN 2019
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