For the diazonium ions,the order of reactivit | vedclass

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(B) The diazo-coupling reaction is an electrophilic aromatic substitution reaction. The reactivity of the diazonium ion towards coupling depends on th

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$I < III < IV < II$

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(B) The diazo-coupling reaction is an electrophilic aromatic substitution reaction. The reactivity of the diazonium ion towards coupling depends on the electrophilicity of the diazonium cation. Greater electron-withdrawing character of the substituent on the benzene ring increases the electrophilicity of the diazonium group,thereby increasing the reactivity. The substituent effects are as follows:$(I)$ $-NMe_2$: Strong $+M$ effect (strongly electron-donating).$(II)$ $-NO_2$: Strong $-M$ effect (strongly electron-withdrawing).$(III)$ $-OCH_3$: $+M$ effect (electron-donating).$(IV)$ $-CH_3$: $+I$ effect (weakly electron-donating).Thus,the electron-withdrawing order is: $-NO_2 > -CH_3 > -OCH_3 > -NMe_2$.Therefore,the order of reactivity is: $(I) < (III) < (IV) < (II)$.

For the diazonium ions,the order of reactivity towards the diazo-coupling with phenol in the presence of dilute $NaOH$ is:
$(I)$ $Me_2N-C_6H_4-N_2^+$
$(II)$ $O_2N-C_6H_4-N_2^+$
$(III)$ $CH_3O-C_6H_4-N_2^+$
$(IV)$ $CH_3-C_6H_4-N_2^+$

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For the diazonium ions,the order of reactivity towards the diazo-coupling with phenol in the presence of dilute $NaOH$ is:$(I)$ $Me_2N-C_6H_4-N_2^+$$(II)$ $O_2N-C_6H_4-N_2^+$$(III)$ $CH_3O-C_6H_4-N_2^+$$(IV)$ $CH_3-C_6H_4-N_2^+$