For the electrophilic substitution reaction i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In electrophilic aromatic substitution,the rate-determining step is the formation of the sigma complex (arenium ion) by the attack of the electrop

Vedclass · Accepted Answer

$k_{C_6H_6} = k_{C_6D_6} = k_{C_6T_6}$

Vedclass · Answer

(A) In electrophilic aromatic substitution,the rate-determining step is the formation of the sigma complex (arenium ion) by the attack of the electrophile on the aromatic ring. Since the $C-H$ (or $C-D$ or $C-T$) bond is not broken in the rate-determining step,there is no primary kinetic isotope effect. Therefore,the rates of nitration for benzene $(C_6H_6)$,hexadeuterobenzene $(C_6D_6)$,and hexatritiobenzene $(C_6T_6)$ are equal. Thus,$k_{C_6H_6} = k_{C_6D_6} = k_{C_6T_6}$.

For the electrophilic substitution reaction involving nitration,which of the following sequences regarding the rate of reaction is true?

Similar Questions

Which of the following Friedel-Crafts reactions is incorrectly written?

Which of the following compounds has the lowest bond dissociation energy for a $C-H$ bond?

Give the name and structure of an aromatic hydrocarbon with the molecular formula $C_{12}H_{10}$ which contains two benzene rings.

Which of the following is true about the following groups when attached to a benzene ring?

In $FCR$ (Friedel-Crafts Reaction),toluene can be prepared by which of the following?

Vedclass Test Series

Exam Paper Generator

Online Exam Module