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(C) The power dissipated in the circuit is given by the formula $P = \frac{V^2}{R_{eq}}$.Given $P = 150 	ext{ W}$ and $V = 15 	ext{ V}$.Substituting

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$6$

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(C) The power dissipated in the circuit is given by the formula $P = \frac{V^2}{R_{eq}}$.Given $P = 150 	ext{ W}$ and $V = 15 	ext{ V}$.Substituting the values:$150 = \frac{(15)^2}{R_{eq}}$$150 = \frac{225}{R_{eq}}$$R_{eq} = \frac{225}{150} = 1.5 \Omega$.The two resistors $R$ and $2 \Omega$ are connected in parallel.Therefore,$\frac{1}{R_{eq}} = \frac{1}{R} + \frac{1}{2}$.$\frac{1}{1.5} = \frac{1}{R} + \frac{1}{2}$.$\frac{1}{R} = \frac{1}{1.5} - \frac{1}{2} = \frac{2}{3} - \frac{1}{2} = \frac{4-3}{6} = \frac{1}{6}$.Thus,$R = 6 \Omega$.

For the given circuit diagram,if the dissipated electrical power is $150 \text{ W}$,find the value of resistance $R$. (in $\Omega$)

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