For the given combination of logic gates,whic | vedclass

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Question

(D) The given circuit consists of an $OR$ gate followed by an $AND$ gate. Let the output of the $OR$ gate be $X$. The inputs to the $OR$ gate are $B$

Vedclass · Accepted Answer

$1, 0, 1$

Vedclass · Answer

(D) The given circuit consists of an $OR$ gate followed by an $AND$ gate. Let the output of the $OR$ gate be $X$. The inputs to the $OR$ gate are $B$ and $C$,so $X = B + C$. The inputs to the $AND$ gate are $A$ and $X$. Therefore,the final output is $Y = A \cdot X = A \cdot (B + C)$. For the output $Y = 1$,both $A$ must be $1$ and $(B + C)$ must be $1$. Checking the options: $A) 0, 0, 0 \implies Y = 0 \cdot (0 + 0) = 0$ $B) 0, 1, 0 \implies Y = 0 \cdot (1 + 0) = 0$ $C) 1, 0, 0 \implies Y = 1 \cdot (0 + 0) = 0$ $D) 1, 0, 1 \implies Y = 1 \cdot (0 + 1) = 1 \cdot 1 = 1$ Thus,the set of inputs $A=1, B=0, C=1$ gives the output $Y=1$.

For the given combination of logic gates,which of the following sets of inputs $A, B,$ and $C$ respectively results in an output $Y = 1$?

Similar Questions

The given truth table is correct for:
$P: 1, 1, 0, 0$
$Q: 1, 0, 1, 0$
$R: 1, 0, 0, 0$

The output of the following circuit is equivalent to which gate?

In Boolean algebra,$Y = A + B$ represents . . . . . .

Which logic gate with inputs $A$ and $B$ performs the same operation as that performed by the following circuit?

The truth table given below corresponds to which logic gate?

$A$ $B$ $X$

$0$ $0$ $0$

$0$ $1$ $1$

$1$ $0$ $1$

$1$ $1$ $1$

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