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(D) The given circuit consists of two $NOR$ gates acting as $NOT$ gates, followed by a $NOR$ gate. Let the inputs be $A$ and $B$.The first two gates a

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$AND$-Gate

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(D) The given circuit consists of two $NOR$ gates acting as $NOT$ gates, followed by a $NOR$ gate. Let the inputs be $A$ and $B$.The first two gates are $NOR$ gates with both inputs tied together. The output of the first gate is $\overline{A+A} = \bar{A}$.The output of the second gate is $\overline{B+B} = \bar{B}$.These outputs are fed into the final $NOR$ gate. The output $Y$ is given by:$Y = \overline{\bar{A} + \bar{B}}$Using De Morgan's theorem, $\overline{\bar{A} + \bar{B}} = \overline{\bar{A}} \cdot \overline{\bar{B}} = A \cdot B$.Thus, the circuit represents an $AND$ gate.$A$$B$$Y = A \cdot B$$0$$0$$0$$0$$1$$0$$1$$0$$0$$1$$1$$1$

For the given digital circuit, identify the logic gate it represents:

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Inputs	Inputs	Outputs
$A$	$B$	$Y$
$0$	$0$	$0$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$1$