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(C) The given circuit represents an $XOR$ gate, which performs the operation $Y = A \oplus B = A \cdot \overline{B} + \overline{A} \cdot B$.For inputs

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$1$, $0$

Vedclass · Answer

(C) The given circuit represents an $XOR$ gate, which performs the operation $Y = A \oplus B = A \cdot \overline{B} + \overline{A} \cdot B$.For inputs $(A=0, B=1)$:$Y = 0 \cdot \overline{1} + \overline{0} \cdot 1 = 0 \cdot 0 + 1 \cdot 1 = 0 + 1 = 1$.For inputs $(A=0, B=0)$:$Y = 0 \cdot \overline{0} + \overline{0} \cdot 0 = 0 \cdot 1 + 1 \cdot 0 = 0 + 0 = 0$.Thus, the outputs are $1$ and $0$ respectively.

For the given logic circuit, the output $Y$ for inputs $(A=0, B=1)$ and $(A=0, B=0)$ respectively are

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Inputs Inputs Outputs
$A$ $B$ $Y$
$0$ $0$ $0$
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The output $Y$ of the given network is :-

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Inputs	Inputs	Outputs
$A$	$B$	$Y$
$0$	$0$	$0$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$1$