For the given reaction:(Cyclohexyl)-CH=CH-(Cy | vedclass

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(A) The reaction of an alkene with hot acidic $KMnO_4$ (oxidative cleavage) results in the cleavage of the $C=C$ double bond.For the given reactant,$1

Vedclass · Accepted Answer

Cyclohexanecarboxylic acid

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(A) The reaction of an alkene with hot acidic $KMnO_4$ (oxidative cleavage) results in the cleavage of the $C=C$ double bond.For the given reactant,$1,2$-dicyclohexylethane,the oxidative cleavage of the double bond yields two molecules of cyclohexanecarboxylic acid as the major product.The reaction is:$(C_6H_{11})CH=CH(C_6H_{11}) \xrightarrow{KMnO_4/H^+} 2 C_6H_{11}COOH$Thus,the major product '$P$' is cyclohexanecarboxylic acid.

For the given reaction:
(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)
'$P$' is:

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For the given reaction:(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)'$P$' is: