For the hypothetical reactionA_{2(g)} + B_{2( | vedclass

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(A) Step $1$: Calculate $\Delta_r H^o$ at $200 \ K$ using the relation $\Delta G^o = \Delta H^o - T \Delta S^o$.$\Delta H_{200}^o = \Delta G_{200}^o +

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$20$

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(A) Step $1$: Calculate $\Delta_r H^o$ at $200 \ K$ using the relation $\Delta G^o = \Delta H^o - T \Delta S^o$.$\Delta H_{200}^o = \Delta G_{200}^o + T \Delta S_{200}^o = 20 \ kJ/mol + (200 \ K 	imes (-20 \ J K^{-1} mol^{-1})) / 1000 = 20 - 4 = 16 \ kJ/mol$.Step $2$: Calculate $\Delta_r H^o$ at $400 \ K$ using Kirchhoff's equation: $\Delta H_{T_2}^o = \Delta H_{T_1}^o + \Delta_r C_P (T_2 - T_1)$.$\Delta H_{400}^o = 16 \ kJ/mol + (20 \ J K^{-1} mol^{-1} 	imes (400 \ K - 200 \ K)) / 1000$.$\Delta H_{400}^o = 16 + (20 	imes 200) / 1000 = 16 + 4 = 20 \ kJ/mol$.

For the hypothetical reaction
$A_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{(g)}$
$\Delta_r G^o$ and $\Delta_r S^o$ are $20 \ kJ/mol$ and $-20 \ J K^{-1} mol^{-1}$ respectively at $200 \ K$.
If $\Delta_r C_P$ is $20 \ J K^{-1} mol^{-1}$ then $\Delta_r H^o$ at $400 \ K$ is.....$kJ/mol$

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For the hypothetical reaction$A_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{(g)}$$\Delta_r G^o$ and $\Delta_r S^o$ are $20 \ kJ/mol$ and $-20 \ J K^{-1} mol^{-1}$ respectively at $200 \ K$.If $\Delta_r C_P$ is $20 \ J K^{-1} mol^{-1}$ then $\Delta_r H^o$ at $400 \ K$ is.....$kJ/mol$