For the ionic reaction: XBrO_3^{-} + YCr^{+3} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The balanced redox reaction is determined by balancing the oxidation and reduction half-reactions.$BrO_3^{-} \rightarrow Br_2$ (Reduction: $Br^{+5

Vedclass · Accepted Answer

$X = 6, Y = 10, Z = 22$

Vedclass · Answer

(C) The balanced redox reaction is determined by balancing the oxidation and reduction half-reactions.$BrO_3^{-} \rightarrow Br_2$ (Reduction: $Br^{+5}$ to $Br^0$,change of $5$ per $Br$,so $10$ per $Br_2$)$Cr^{+3} \rightarrow HCrO_4^{-}$ (Oxidation: $Cr^{+3}$ to $Cr^{+6}$,change of $3$ per $Cr$)To balance the electrons,multiply the reduction half by $3$ and the oxidation half by $10$ (or simplify to $3$ and $5$ for $Br_2$ and $Cr$ respectively).$6BrO_3^{-} + 10Cr^{+3} + 22H_2O \rightarrow 3Br_2 + 10HCrO_4^{-} + 34H^{+}$Comparing coefficients,we get $X = 6, Y = 10, Z = 22$.

For the ionic reaction: $XBrO_3^{-} + YCr^{+3} + ZH_2O \rightarrow pBr_2 + qHCrO_4^{-} + rH^{+}$

Similar Questions

Assign $A, B, C, D$ from the given type of reaction for the following chemical equation:
$Mg_{(s)} + 2HCl_{(aq)} \longrightarrow MgCl_{2(aq)} + H_{2(g)}$

$2 IO_3^- + x I^- + 12 H^+ \rightarrow 6 I_2 + 6 H_2 O$. What is the value of $x$?

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$3PbS \downarrow + 8HNO_3(dil.) \longrightarrow 3Pb(NO_3)_2 + 3S + 2NO \uparrow $

For the balanced equation $NO_3^- + 4H^+ + ne^- \to 2H_2O + NO$,the value of $n$ is ........

Which compound is formed when $H_2S$ gas is passed through an acidic solution of $KMnO_4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module