For the oxidation of $0.2 \text{ M} \text{ FeSO}_4$ solution,$0.965 \text{ A}$ current is passed through it for $1 \text{ hour}$. The volume of the solution that is oxidised in $\text{mL}$ is:

  • A
    $70$
  • B
    $80$
  • C
    $60$
  • D
    $90$

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