For the photoelectric effect,which of the fol | vedclass

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(C) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{\max})$ of emitted photoelectrons is given by $K_{\max} = h
u - \p

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$III$ and $IV$ only

Vedclass · Answer

(C) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{\max})$ of emitted photoelectrons is given by $K_{\max} = h
u - \phi$,where $h$ is Planck's constant,$
u$ is the frequency of incident light,and $\phi$ is the work function of the metal.$1$. Statement $I$ is incorrect because $K_{\max}$ depends directly on the frequency $
u$.$2$. Statement $II$ is incorrect because the photoelectric effect depends on the frequency of light being greater than the threshold frequency $(
u_0)$,regardless of intensity.$3$. Statement $III$ is correct because $K_{\max}$ depends only on the frequency of incident light,not on its intensity.$4$. Statement $IV$ is correct because as frequency $
u$ increases,$K_{\max} = h
u - \phi$ also increases.Thus,statements $III$ and $IV$ are correct.

Similar Questions

The stopping potential for a photoelectric emission process is $10 \ V$. The maximum kinetic energy of the electrons ejected in the process is [Charge on electron $e = 1.6 \times 10^{-19} \ C$]

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By the photoelectric effect,Einstein proved:

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